Find the distance between points of intersection of
Lines 
= 
= 
& 
= 
= z and
Lines 
= ( 
+ 
− 
) + λ (3 
− 
) & 
= (4 
− 
) + μ (2 
+ 3 
)
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
( 
)
Sol. 
(Let) ... (1)
⇒ (2r + 1, 3r + 2, 4r + 3) represents any point on (1)
= 
... (2)
To find point of intersection of (1) and (2)
⇒ 
⇒ 4r – 6 = 15r + 5 ⇒ 11r = – 11 ⇒ r = – 1
∴ point of intersection of (1) and (2) is (– 1, – 1, – 1)
... (1) 
... (2)
For their point of intersection
3 λ + 1 = 4 + 2 μ ⇒ 3 λ – 2 μ – 3 = 0 ... (3)
1 – λ = 0 ⇒ λ = 1 ... (4)
and – 1 = – 1 + 3 μ μ = 0
∴ point of intersection is (4, 0, – 1)
∴ required distance = 
= 
= 
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